1/(w^2+2w-24)

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Solution for 1/(w^2+2w-24) equation: 


D( w )

w^2+2*w-24 = 0

w^2+2*w-24 = 0

w^2+2*w-24 = 0

w^2+2*w-24 = 0

DELTA = 2^2-(-24*1*4)

DELTA = 100

DELTA > 0

w = (100^(1/2)-2)/(1*2) or w = (-100^(1/2)-2)/(1*2)

w = 4 or w = -6

w in (-oo:-6) U (-6:4) U (4:+oo)

1/(w^2+2*w-24) = 0

w^2+2*w-24 = 0

w^2+2*w-24 = 0

DELTA = 2^2-(-24*1*4)

DELTA = 100

DELTA > 0

w = (100^(1/2)-2)/(1*2) or w = (-100^(1/2)-2)/(1*2)

w = 4 or w = -6

(w+6)*(w-4) = 0

1/((w+6)*(w-4)) = 0

w belongs to the empty set

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